Power, Electronic Systems, Applications and Resources on Electrical and Electronic Project-Thesis: Full Controlled Rectifier

Full Controlled Rectifier with R Load

If α= 0° ,The output will be same as a Full Uncontrolled Rectifier that uses DIODE.

Average Load/Output Voltage

${V_0} = \frac{2}{{2\pi }}\int_\alpha ^\pi {\sqrt 2 V\sin \theta d\theta }$

$= \frac{{\sqrt 2 V}}{\pi }\left( {1 + \cos \alpha } \right)$

Average Load/Output Current

${I_0} = \frac{{{V_0}}}{R}$

Full Controlled Rectifier with DC Motor Load
For 90° < α < 180°

Average Load/Output Voltage
${V_0} = \frac{2}{{2\pi }}\int_\alpha ^{\pi + \alpha } {{V_m}\sin \theta d\theta }$

$= \frac{{2{V_m}}}{\pi }\cos \alpha$

Average Load/Output Current

V_o= I_oR_a+ E_a

E_a = armature back emf.

For 90° < α < 180°

Converter Output Characteristics for continuous load current

For fully controlled rectifier, the DC Motor operates in two modes.
1. Rectification [As Motoring]
V₀ = positive
E_a = Positive
I_o= positive
Power Flow (+ve) from input AC to DC machine
2. Inversion [As Regenerative Braking]
V₀ = negative
E_a = negative
I_o= positive
Power Flow (-ve) from DC machine to AC supply

The output voltage can be varied from a maximum of 2Vm/π to a minimum of zero as the firing angle a varies from zero to π. The rms output voltage is given by

${V_{rms}} = {\left[ {\frac{2}{{2\pi }}\int\limits_\alpha ^\pi {V_m^2{{\sin }^2}\omega td\left( {\omega t} \right)} } \right]^{\frac{1}{2}}}$

${V_{rms}} = \frac{{{V_m}}}{{\sqrt 2 }}{\left[ {\frac{1}{\pi }\left( {\pi - \alpha + \frac{{\sin 2\alpha }}{2}} \right)} \right]^{\frac{1}{2}}}$

previous Performance of Single-phase, half-wave controlled rectifiers

next Single-Phase Full Converter with RL load

Power, Electronic Systems, Applications and Resources on Electrical and Electronic Project-Thesis

Full Controlled Rectifier

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